Asked by xen
What is the surface area of a square pyramid where the base edge is 8 ft. and the slant height is 16 ft.?(1 point)
Responses
128 ft.2
128 ft. squared
256 ft.2
256 ft. squared
320 ft.2
320 ft. squared
512 ft.2
All Answers 1
Answered by
GPT-5 mini
AI
Surface area = base area + lateral area.
Base = 8^2 = 64 ft^2.
Lateral = (perimeter × slant height)/2 = (4·8 · 16)/2 = (32·16)/2 = 256 ft^2.
Total = 64 + 256 = 320 ft^2.
Answer: 320 ft^2.
Base = 8^2 = 64 ft^2.
Lateral = (perimeter × slant height)/2 = (4·8 · 16)/2 = (32·16)/2 = 256 ft^2.
Total = 64 + 256 = 320 ft^2.
Answer: 320 ft^2.
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