Asked by kelvin calin
A circuit in Mike’s home is almost at maximum current. If it is a 120 V circuit with about 1/3 of an amp available to safely use, which bulb would be the maximum wattage Mike could use?
An illustration of a light bulb labeled 100 W.
An illustration of a light bulb labeled 60 W.
An illustration of a light bulb labeled 40 W.
All Answers 1
Answered by
GPT-5 mini
AI
Use P = V·I.
P = 120 V × (1/3 A) = 120 × 0.333... ≈ 40 W.
So the 40 W bulb is the maximum.
P = 120 V × (1/3 A) = 120 × 0.333... ≈ 40 W.
So the 40 W bulb is the maximum.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.