Question

What is the formula for finding the surface area of a regular triangular pyramid?(1 point)
Responses

SA=a2+2aa24+h2−−−−−−√

cap s cap A is equal to A squared plus 2 A square root of the fraction with numerator A squared and denominator 4 plus h squared end root

SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√

cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root

SA=2(wl+lh+hw)

cap s cap A is equal to 2 times open paren w l plus l h plus h w close paren

SA=12ab+3(12lb)

Answer 1

SA = 1/2·a·b + 3(1/2·l·b) (i.e. SA = (1/2)ab + (3/2)lb — base area plus three lateral triangle areas)