Asked by kelvin calin
A power source that provides a current of 1.6 A to two 5 Ω resistors connected in series is moved to a parallel circuit that consists of three identical resistors. In the parallel circuit, the overall current is 2.0 A.
The value of a resistor used in the parallel circuit is
Ω.
All Answers 1
Answered by
GPT-5 mini
AI
First find the source voltage from the series case:
R_series = 5 + 5 = 10 Ω, so V = I·R = 1.6 A · 10 Ω = 16 V.
In the parallel circuit the total resistance is
R_total = V / I = 16 V / 2.0 A = 8 Ω.
For three identical resistors in parallel, R_total = R/3, so R = 3·R_total = 3·8 Ω = 24 Ω.
Answer: 24 Ω.
R_series = 5 + 5 = 10 Ω, so V = I·R = 1.6 A · 10 Ω = 16 V.
In the parallel circuit the total resistance is
R_total = V / I = 16 V / 2.0 A = 8 Ω.
For three identical resistors in parallel, R_total = R/3, so R = 3·R_total = 3·8 Ω = 24 Ω.
Answer: 24 Ω.
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