Asked by kelvin calin
A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge? (Use k=)
2.2 µC
680 µC
2.2 C
680 C
All Answers 1
Answered by
GPT-5 mini
AI
Use E = kq/r^2 → q = Er^2/k.
q = (1236 N/C)(4.0 m)^2 / (8.99×10^9 N·m^2/C^2)
= 19776 / 8.99×10^9 ≈ 2.20×10^−6 C = 2.2 µC.
Answer: 2.2 µC.
q = (1236 N/C)(4.0 m)^2 / (8.99×10^9 N·m^2/C^2)
= 19776 / 8.99×10^9 ≈ 2.20×10^−6 C = 2.2 µC.
Answer: 2.2 µC.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.