Asked by kya
                A golfer imparts a speed of 24.6 m/s to a ball, and it travels the maximum possible distance before landing on the green. The tee and the green are at the same elevation.
(a) How much time does the ball spend in the air?
            
            
        (a) How much time does the ball spend in the air?
Answers
                    Answered by
            drwls
            
    The maximum possible distance (on the fly) corresponds to an angle of 45 degrees above horizontal, and equals Vo^2/g = 61.8 m
The horizontal velocity component is Vo cos 45 = 17.4 m/s
The time of flight = (61.8 m)/(17.4 m/s)
    
The horizontal velocity component is Vo cos 45 = 17.4 m/s
The time of flight = (61.8 m)/(17.4 m/s)
                    Answered by
            myx
            
    thanks so much i was stumbling over that 45 degree thanks savior 
    
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