Question

Use any method to locate the zeros of y=−3x2+12x+15
.(1 point)
Responses

(1,0)(−5,0)

left parenthesis 1 comma 0 right parenthesis left parenthesis negative 5 comma 0 right parenthesis

There are no zeros.
There are no zeros.

(0,15)

left parenthesis 0 comma 15 right parenthesis

(−1,0)(5,0)

Answer 1

Factor or solve the quadratic:
-3x^2 + 12x + 15 = -3(x^2 - 4x - 5) = -3(x - 5)(x + 1).

Zeros are x = 5 and x = −1, so the points are (−1, 0) and (5, 0).