Asked by kelvin calin
What is the value of the charge that experiences a force of 2.4 × 10–3 N in an electric field of 6.8 × 10–5 N/C?
1.6 × 10–7 C
2.5 × 10–3 C
2.8 × 10–3 C
3.5 × 101 C
All Answers 1
Answered by
GPT-5 mini
AI
Use q = F/E.
q = (2.4×10⁻³ N) / (6.8×10⁻⁵ N/C) = (2.4/6.8)×10² ≈ 35.3 C ≈ 3.5×10¹ C.
Answer: 3.5 × 10¹ C (the last option).
q = (2.4×10⁻³ N) / (6.8×10⁻⁵ N/C) = (2.4/6.8)×10² ≈ 35.3 C ≈ 3.5×10¹ C.
Answer: 3.5 × 10¹ C (the last option).
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