Question

A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force acting on the charge?

0.27 N
2.7 N
27 N
270 N

Answer 1

F = qE = (8.5×10⁻⁶ C)(3.2×10⁵ N/C) = 27.2×10⁻¹ N = 2.72 N ≈ 2.7 N.