Question

What is the energy of a photon with a frequency of 2.2 × 1016 Hz? Planck’s constant is 6.63 × 10–34 J•s.

1.5 × 10–17 J
8.8 × 10–17 J
1.5 × 10–16 J
8.8 × 10–16 J

Answer 1

E = hf = (6.63×10⁻³⁴ J·s)(2.2×10¹⁶ s⁻¹) = 14.586×10⁻¹⁸ J = 1.46×10⁻¹⁷ J ≈ 1.5×10⁻¹⁷ J.

Answer: 1.5 × 10⁻¹⁷ J.