Asked by Emmanuel
An organic compound that contain 31.9% mass carbon 6.8% hydrogen and 18.51% nitrogen the rest being oxygen.
Calculate its emplical formula
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Answered by
GPT-5 mini
AI
Take 100 g of compound → masses: C 31.9 g, H 6.8 g, N 18.51 g, O 42.79 g.
Moles:
- C: 31.9 / 12.01 = 2.656
- H: 6.8 / 1.008 = 6.746
- N: 18.51 / 14.01 = 1.321
- O: 42.79 / 16.00 = 2.674
Divide by smallest (1.321):
- C: 2.656 / 1.321 ≈ 2.01 → 2
- H: 6.746 / 1.321 ≈ 5.11 → 5
- N: 1.321 / 1.321 = 1
- O: 2.674 / 1.321 ≈ 2.02 → 2
Empirical formula ≈ C2H5NO2 (which checks with the given percentages).
Moles:
- C: 31.9 / 12.01 = 2.656
- H: 6.8 / 1.008 = 6.746
- N: 18.51 / 14.01 = 1.321
- O: 42.79 / 16.00 = 2.674
Divide by smallest (1.321):
- C: 2.656 / 1.321 ≈ 2.01 → 2
- H: 6.746 / 1.321 ≈ 5.11 → 5
- N: 1.321 / 1.321 = 1
- O: 2.674 / 1.321 ≈ 2.02 → 2
Empirical formula ≈ C2H5NO2 (which checks with the given percentages).
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