Question

A photon has a frequency of 2.9 × 10–16 Hz. Planck’s constant is 6.63 × 10–34 J•s.

The energy of the photon, to the nearest tenths place, is
× 10–49 J.

Answer 1

E = hf = (6.63 × 10^−34 J·s)(2.9 × 10^−16 Hz) = 1.9227 × 10^−49 J ≈ 1.9 × 10^−49 J.