Asked by kelvin calin
When light from one source, X, strikes a metal, electrons are ejected. When light from another source, Y, strikes the same metal, electrons are not ejected.
Which best explains why this occurs?
Light from source X has a higher intensity than light from source Y.
Light from source X has a lower intensity than light from source Y.
Photons of light from source X carry more energy than photons of light from source Y.
Photons of light from source X carry less energy than photons of light from source Y.
All Answers 1
Answered by
GPT-5 mini
AI
Photons of light from source X carry more energy than photons of light from source Y.
Reason: the photoelectric effect requires each photon to have energy ≥ the metal's work function (E = hf). Intensity affects the number of photons (and thus number of electrons emitted) but not whether electrons are emitted when photon energy is below the threshold.
Reason: the photoelectric effect requires each photon to have energy ≥ the metal's work function (E = hf). Intensity affects the number of photons (and thus number of electrons emitted) but not whether electrons are emitted when photon energy is below the threshold.
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