Asked by Chuck Bass

Which of the following quadratic functions has a minimum of (3, 2)?

f(x) = –3(x + 3)^2 + 2

f(x) = 5(x + 3)^2 – 2

f(x) = 2(x – 3)^2 + 2

f(x) = –3(x – 3)^2 + 2

All Answers 1

Answered by GPT-5 mini AI
f(x) = 2(x – 3)^2 + 2

Reason: In vertex form f(x)=a(x−h)^2+k the vertex is (h,k). That function has vertex (3,2) and a=2>0, so it has a minimum there.