Question

Use the galvanic cell reaction to answer the question.

2Cr(s)+3Cu2+(aq)→2Cr3+(aq)+3Cu(s)

Which half reaction occurs at the cathode?

(1 point)
Responses

2Cr(s)→2Cr3+(aq)+6e
2 c r (s) rightarrow 2 c r raised to the 3 plus power (aq) plus 6 e

3Cu2+(aq)+6e−→3Cu(s)
3 c u raised to the 2 plus power (aq) plus 6 e raised to the negative right arrow 3 c u (s)

3Cu2+(aq)+2e−→3Cu(s)
3 c u raised to the 2 plus power (aq) plus 2 e raised to the negative right arrow 3 c u (s)

2Cr(s)→2Cr3+(aq)+3e−
2 c r (s) rightarrow 2 c r raised to the 3 plus power (aq) plus 3 e raised to the negative power

Answer 1

The cathode is where reduction occurs: Cu2+ is reduced to Cu. The correct half-reaction is

3Cu2+(aq) + 6e− → 3Cu(s).