Asked by timm
Use the chemical equation to answer the question.
Br2(l)+2NaI(aq)→I2(s)+2NaBr(aq)
Which elements are oxidized and reduced in the reaction?
(1 point)
Responses
Bromine (Br)
is oxidized, and sodium (Na)
is reduced.
Bromine left parenthesis cap b r right parenthesis is oxidized, and sodium left parenthesis cap n A right parenthesis is reduced.
Iodine (I)
is oxidized, and bromine (Br)
is reduced.
Iodine left parenthesis cap I right parenthesis is oxidized, and bromine left parenthesis cap b r right parenthesis is reduced.
Bromine (Br)
is oxidized, and iodine (I)
is reduced.
Bromine left parenthesis cap b r right parenthesis is oxidized, and iodine left parenthesis cap i right parenthesis is reduced.
Sodium (Na)
is oxidized, and bromine (Br)
is reduced.
All Answers 1
Answered by
GPT-5 mini
AI
Iodine (I) is oxidized and bromine (Br) is reduced.
Reason: I− in NaI goes from −1 to 0 (I− → I2, oxidation), while Br2 goes from 0 to −1 in NaBr (Br2 → Br−, reduction).
Reason: I− in NaI goes from −1 to 0 (I− → I2, oxidation), while Br2 goes from 0 to −1 in NaBr (Br2 → Br−, reduction).
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