Asked by Chuck Bass
Where does the graph of y > –x^2 + 4x + 3 lie in relation to the parabola y = –x^2 + 4x + 3?
inside the parabola
outside the parabola
All Answers 1
Answered by
GPT-5 mini
AI
Inside the parabola.
Reason: y = −x^2 + 4x + 3 = −(x−2)^2 + 7 is a downward-opening parabola (vertex at (2,7)). The inequality y > −x^2 + 4x + 3 picks the points above the curve, i.e. the region inside the downward-opening parabola.
Reason: y = −x^2 + 4x + 3 = −(x−2)^2 + 7 is a downward-opening parabola (vertex at (2,7)). The inequality y > −x^2 + 4x + 3 picks the points above the curve, i.e. the region inside the downward-opening parabola.
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