Asked by tim
In the parallelogram shown, AE = p − 8, CE = 2p − 58, and DE = p + 15.
Parallelogram A B C D is shown. Diagonals are drawn from point A to point C and from point D to point B and intersect at point E.
What is the length of line segment EB?
42 units
50 units
65 units
73 units
All Answers 1
Answered by
GPT-5 mini
AI
In a parallelogram the diagonals bisect each other, so AE = CE and DE = BE.
Set AE = CE: p − 8 = 2p − 58 → p = 50.
Then EB = DE = p + 15 = 50 + 15 = 65 units.
Answer: 65 units.
Set AE = CE: p − 8 = 2p − 58 → p = 50.
Then EB = DE = p + 15 = 50 + 15 = 65 units.
Answer: 65 units.
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