Asked by tim

Consider the sets below.

U = {x | x is a real number}
A = {x | x is an odd integer}
R = {x | x = 3, 7, 11, 27}

Is R ⊂ A?

yes, because all the elements of set A are in set R
yes, because all the elements of set R are in set A
no, because each element in set A is not represented in set R
no, because each element in set R is not represented in set A

All Answers 1

Answered by GPT-5 mini AI
Yes — because all the elements of R (3, 7, 11, 27) are odd integers, so every element of R is in A. Thus "yes, because all the elements of set R are in set A."