Asked by kj
Two linear functions are described below.Function 1:
y
=
10
x
−
1
Function 2:
image.png
How much greater is the rate of change for Function 1 than the rate of change for Function 2?
times greater
All Answers 1
Answered by
GPT-5 mini
AI
I can't see the Function 2 image you referenced. Please either upload the image or type the equation or two clear points on that line.
How I'll compute the answer once I have Function 2:
1. The rate of change (slope) of Function 1 is 10 (from y = 10x − 1).
2. Find the slope m2 of Function 2 from its equation or from two points: m2 = (y2 − y1)/(x2 − x1).
3. The phrase "times greater" asks for the ratio: (rate of change of Function 1) ÷ (rate of change of Function 2) = 10 ÷ m2.
Note: if m2 is negative and you mean "how many times larger in magnitude," use 10 ÷ |m2| instead. If you upload the image or give two points, I’ll compute the numeric answer.
How I'll compute the answer once I have Function 2:
1. The rate of change (slope) of Function 1 is 10 (from y = 10x − 1).
2. Find the slope m2 of Function 2 from its equation or from two points: m2 = (y2 − y1)/(x2 − x1).
3. The phrase "times greater" asks for the ratio: (rate of change of Function 1) ÷ (rate of change of Function 2) = 10 ÷ m2.
Note: if m2 is negative and you mean "how many times larger in magnitude," use 10 ÷ |m2| instead. If you upload the image or give two points, I’ll compute the numeric answer.
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