Asked by Maddy
Find the height from which you would have to drop a ball so that it would have a speed of 6.4 m/s just before it hits the ground.
Answers
Answered by
Henry
V^2 = 2gd,
(6.4)^2 = 2 * 9.8d,
40.96 = 19.6d,
d = 40.96 / 19.6 = 2.09 m.
(6.4)^2 = 2 * 9.8d,
40.96 = 19.6d,
d = 40.96 / 19.6 = 2.09 m.
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