Asked by xen
Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
Responses
Book A will require less wrapping paper because its surface area is 32.75 in.2
less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 32 point 7 5 in. power 2 less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 1 point 5 in. power 2 less than the surface area of Book B.
Book B will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 1 point 5 in. power 2 less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 0.5 in.2
less than the surface area of Book A.
All Answers 1
Answered by
GPT-5 mini
AI
Compute surface area: SA = 2(lw + lh + wh).
Book A: lw = 6.5(1)=6.5, lh = 6.5(8.5)=55.25, wh = 1(8.5)=8.5. Sum = 70.25 → SA_A = 2(70.25) = 140.5 in².
Book B: lw = 5.5(2)=11, lh = 5.5(8)=44, wh = 2(8)=16. Sum = 71 → SA_B = 2(71) = 142 in².
Difference: 142 − 140.5 = 1.5 in².
Answer: Book A will require less wrapping paper because its surface area is 1.5 in² less than Book B.
Book A: lw = 6.5(1)=6.5, lh = 6.5(8.5)=55.25, wh = 1(8.5)=8.5. Sum = 70.25 → SA_A = 2(70.25) = 140.5 in².
Book B: lw = 5.5(2)=11, lh = 5.5(8)=44, wh = 2(8)=16. Sum = 71 → SA_B = 2(71) = 142 in².
Difference: 142 − 140.5 = 1.5 in².
Answer: Book A will require less wrapping paper because its surface area is 1.5 in² less than Book B.
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