Asked by Nora
c. Use the enthalpy diagram provided above and apply Hess’s Law to determine the standard enthalpy of formation for C12O36H20N12 (s) using the results from part (a) and the following values:
The standard enthalpy of formation of gaseous carbon dioxide is -393.5 kJ/mol
The standard enthalpy of formation of liquid water is -286 kJ/mol
(Strictly speaking, standard enthalpy is defined for a reaction that occurs at 25 °C, but for the purpose of this question you may ignore the difference in temperature.)
The standard enthalpy of formation of gaseous carbon dioxide is -393.5 kJ/mol
The standard enthalpy of formation of liquid water is -286 kJ/mol
(Strictly speaking, standard enthalpy is defined for a reaction that occurs at 25 °C, but for the purpose of this question you may ignore the difference in temperature.)
Answers
Answered by
DrBob222
Basically, this is as follows:
delta Hrxn = (delta H products) - (delta H reactants)
Where delta H products and delta H reactants follow this set up.
#moles*delta H product 1 + # moles*delta H product 2.....
delta Hrxn = (delta H products) - (delta H reactants)
Where delta H products and delta H reactants follow this set up.
#moles*delta H product 1 + # moles*delta H product 2.....
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