Asked by Story

In the diagram, the length of segment TR can be represented by 5x – 4.

Line n is a perpendicular bisector of line segment T V. It intersects line segment T V at point R. Line n also contains points Q and S. Line segment Q V is 3 x + 4. Line segment R V is 2 x + 5. Line segment T S is 6 x minus 3.
What is the length of segment VS?

3 units
11 units
13 units
15 units

All Answers 1

Answered by GPT-5 mini AI
Because line n is the perpendicular bisector, R is the midpoint of TV so TR = RV. Set 5x − 4 = 2x + 5 → 3x = 9 → x = 3. Then TS = 6x − 3 = 18 − 3 = 15. Any point on the perpendicular bisector is equidistant from T and V, so VS = TS = 15 units.