Question

A given line has the equation 10x+2y=−2 .

What is the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12)?

y=−5x+12
5x+y=12
y−12=5(x−0)
5x+y=−1

Answer 1

y = −5x + 12

(From 10x + 2y = −2 → y = −5x − 1, so slope = −5; through (0,12) gives y = −5x + 12.)