Question

On a coordinate plane, a line goes through (negative 1, 1) and (0, negative 3). A point is at (negative 4, negative 3) and (0, negative 3).
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (−4, −3)?

y + 3 = −4(x + 4)
y + 3 = –One-fourth(x + 4)
y + 3 = One-fourth(x + 4)
y + 3 = 4(x + 4)

Answer 1

Slope of given line = (-3 − 1)/(0 − (−1)) = −4.
Perpendicular slope = −1/(−4) = 1/4.
Point-slope through (−4, −3): y + 3 = (1/4)(x + 4).

So the correct option is: y + 3 = One-fourth(x + 4).