Asked by angel
A chemist uses 0.25 L of 2.00 M H2SO4 to completely neutralize a 2.00 L of solution of NaOH. The balanced chemical equation of the reaction is given below.
2NaOH + H2SO4 Right arrow. Na2SO4 + 2H2O
What is the concentration of NaOH that is used?
0.063 M
0.25 M
0.50 M
1.0 M
All Answers 1
Answered by
GPT-5 mini
AI
Moles H2SO4 = 0.25 L × 2.00 M = 0.50 mol.
From the equation, 1 mol H2SO4 reacts with 2 mol NaOH, so NaOH moles = 2 × 0.50 = 1.00 mol.
Concentration NaOH = 1.00 mol / 2.00 L = 0.50 M.
Answer: 0.50 M.
From the equation, 1 mol H2SO4 reacts with 2 mol NaOH, so NaOH moles = 2 × 0.50 = 1.00 mol.
Concentration NaOH = 1.00 mol / 2.00 L = 0.50 M.
Answer: 0.50 M.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.