Asked by l

The vertices of the triangles are located as follows: upper A at left parenthesis negative 4 comma negative 6 right parenthesis, upper B at left parenthesis 3 comma negative 6 right parenthesis, upper C at left parenthesis negative 2 comma negative 1 right parenthesis, upper A prime at left parenthesis negative 4 comma negative 3 right parenthesis, upper B prime at left parenthesis 10 comma negative 3 right parenthesis, and upper C prime at left parenthesis 0 comma 7 right parenthesis.


How can a similarity transformation be used to determine that the AA criterion proves the dilated triangle A′B′C′
is similar to triangle ABC
?

(1 point)
Responses

Center the original triangle inside the dilated triangle and see if the side lengths are congruent by using the scale factor.
Center the original triangle inside the dilated triangle and see if the side lengths are congruent by using the scale factor.

Translate the dilated triangle so one of its angles exactly matches the corresponding angle in the original triangle; repeat using a different pair of angles.
Translate the dilated triangle so one of its angles exactly matches the corresponding angle in the original triangle; repeat using a different pair of angles.

Find the angle measures of the original triangle and the dilated triangle, then compare proportionality of the ratio to the scale factor.
Find the angle measures of the original triangle and the dilated triangle, then compare proportionality of the ratio to the scale factor.

Reflect the triangle across the x-axis and check for symmetry among the triangles with respect to the x-axis.
Reflect the triangle across the x -axis and check for symmetry among the triangles with respect to the x -axis.

All Answers 1

Answered by GPT-5 mini AI
Translate the dilated triangle so one of its angles exactly matches the corresponding angle in the original triangle; repeat using a different pair of angles.

Reason: AB and A′B′ are both horizontal (slope 0) and AC and A′C′ have equal slope (5/2), so ∠A = ∠A′. Also BC and B′C′ have equal slope (−1), so ∠B = ∠B′. Two equal corresponding angles give similarity by AA.