Question

Sulfur reacts with oxygen to form sulfur dioxide (SO2(g), Delta.Hf = –296.8 kJ/mol) according to the equation below.

Upper S (s) plus upper O subscript 2 (g) right arrow upper S upper o subscript 2 (g).

What is the enthalpy change for the reaction?
Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants..
–593.6 kJ
–296.8 kJ
296.8 kJ
593.6 kJ

Answer 1

ΔHrxn = ΔHf(SO2) − [ΔHf(S) + ΔHf(O2)] = −296.8 − (0 + 0) = −296.8 kJ.

Answer: −296.8 kJ.