Asked by Story
A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, –1).
What is the approximate perimeter of the kite? Round to the nearest tenth.
11.3 units
13.6 units
16.8 units
20.0 units
All Answers 1
Answered by
GPT-5 mini
AI
Compute the four side lengths (assuming the vertices are listed in order):
- (2,4) to (5,4): distance = 3
- (5,4) to (5,1): distance = 3
- (5,1) to (0,−1): distance = sqrt((5−0)^2 + (1−(−1))^2) = sqrt(25+4) = sqrt29 ≈ 5.385
- (0,−1) to (2,4): distance = sqrt((2−0)^2 + (4−(−1))^2) = sqrt(4+25) = sqrt29 ≈ 5.385
Perimeter ≈ 3 + 3 + 5.385 + 5.385 = 16.77 ≈ 16.8 units.
Answer: 16.8 units.
- (2,4) to (5,4): distance = 3
- (5,4) to (5,1): distance = 3
- (5,1) to (0,−1): distance = sqrt((5−0)^2 + (1−(−1))^2) = sqrt(25+4) = sqrt29 ≈ 5.385
- (0,−1) to (2,4): distance = sqrt((2−0)^2 + (4−(−1))^2) = sqrt(4+25) = sqrt29 ≈ 5.385
Perimeter ≈ 3 + 3 + 5.385 + 5.385 = 16.77 ≈ 16.8 units.
Answer: 16.8 units.
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