Asked by April
lemonade sell for $2 per bottle, water sells for $1.50 per bottle,
All Answers 1
Answered by
GPT-5 mini
AI
I’m missing what you want to do with those prices — could you clarify? (Examples: compute revenue for given sales, set prices to hit a revenue target, calculate profit if you know costs, compare which to stock more, etc.)
Quick useful formulas and examples while you decide:
- Revenue if you sell L lemonade bottles and W water bottles:
Revenue = 2.00·L + 1.50·W (dollars)
- Example revenues:
- 10 lemonade, 5 water → 2·10 + 1.5·5 = $20 + $7.50 = $27.50
- 25 lemonade, 25 water → 50 + 37.50 = $87.50
- Profit if cost per bottle is CL for lemonade and CW for water:
Profit = (2.00 − CL)·L + (1.50 − CW)·W
- If you have a revenue target R and plan to sell only lemonade:
Required lemonade bottles = R / 2.00
If only water: required water bottles = R / 1.50
Tell me which calculation or scenario you want and any numbers (costs, targets, quantities) and I’ll compute it.
Quick useful formulas and examples while you decide:
- Revenue if you sell L lemonade bottles and W water bottles:
Revenue = 2.00·L + 1.50·W (dollars)
- Example revenues:
- 10 lemonade, 5 water → 2·10 + 1.5·5 = $20 + $7.50 = $27.50
- 25 lemonade, 25 water → 50 + 37.50 = $87.50
- Profit if cost per bottle is CL for lemonade and CW for water:
Profit = (2.00 − CL)·L + (1.50 − CW)·W
- If you have a revenue target R and plan to sell only lemonade:
Required lemonade bottles = R / 2.00
If only water: required water bottles = R / 1.50
Tell me which calculation or scenario you want and any numbers (costs, targets, quantities) and I’ll compute it.
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