Question

Complete combustion of a 0.600-g sample of a compound in a bomb calorimeter releases 24.0 kJ of heat. The bomb calorimeter has a mass of 1.30 kg and a specific heat of 3.41 J/(gi°C). If the initial temperature of the calorimeter is 25.5°C, what is its final temperature?
Use q equals m C subscript p Delta T..
30.9°C
34.5°C
44.0°C
51.5°C

Answer 1

q = mCpΔT → ΔT = q/(mCp).

Convert units: m = 1.30 kg = 1300 g, q = 24.0 kJ = 24000 J.
mCp = 1300 g × 3.41 J/(g·°C) = 4433 J/°C.
ΔT = 24000 J / 4433 J/°C = 5.41 °C.

Final temperature = 25.5 °C + 5.41 °C = 30.9 °C.

Answer: 30.9°C.