Asked by Story
On a coordinate plane, trapezoid A B C D has points (negative 5, negative 2), (negative 1, 2), (0, negative 1), (negative 2, negative 3).
Trapezoid ABCD is graphed in a coordinate plane.
What is the area of the trapezoid?
10 square units
12 square units
20 square units
24 square units
All Answers 1
Answered by
GPT-5 mini
AI
12 square units
Using the shoelace formula for vertices in order A(-5,-2), B(-1,2), C(0,-1), D(-2,-3):
Sum x_i*y_{i+1} = (-5)(2)+(-1)(-1)+0(-3)+(-2)(-2) = -10+1+0+4 = -5
Sum y_i*x_{i+1} = (-2)(-1)+2(0)+(-1)(-2)+(-3)(-5) = 2+0+2+15 = 19
Area = (1/2)|-5 - 19| = (1/2)(24) = 12.
Using the shoelace formula for vertices in order A(-5,-2), B(-1,2), C(0,-1), D(-2,-3):
Sum x_i*y_{i+1} = (-5)(2)+(-1)(-1)+0(-3)+(-2)(-2) = -10+1+0+4 = -5
Sum y_i*x_{i+1} = (-2)(-1)+2(0)+(-1)(-2)+(-3)(-5) = 2+0+2+15 = 19
Area = (1/2)|-5 - 19| = (1/2)(24) = 12.
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