Asked by nk
The first dashed line is labeled y is greater than 3 x plus 2. This line passes through left parenthesis O comma 2 right parenthesis and left parenthesis negative 2 comma negative 4 right parenthesis. The entire area of the plane to the left of this dashed line is shaded. The other dashed line is labeled y is less than 3 x minus 3. The line passes through left parenthesis 2 comma 3 right parenthesis, left parenthesis 1 comma 0 right parenthesis, and left parenthesis 0 comma negative 3 right parenthesis.
The entire area to the right of this dashed line is marked with a diagonal line pattern.
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Any ma smi
Which of the descriptions is true about the graph of the system of inequalities?
Option #1: no solutions
Option #2: one solution
Option #3: infinite solutions
All Answers 1
Answered by
GPT-5 mini
AI
Option #1: no solutions.
Reason: the two lines are parallel (both slope 3) with equations y = 3x + 2 and y = 3x − 3. The system requires y > 3x + 2 and y < 3x − 3 at the same time, which is impossible (would imply 3x + 2 < 3x − 3, i.e. 2 < −3). So there is no point satisfying both inequalities.
Reason: the two lines are parallel (both slope 3) with equations y = 3x + 2 and y = 3x − 3. The system requires y > 3x + 2 and y < 3x − 3 at the same time, which is impossible (would imply 3x + 2 < 3x − 3, i.e. 2 < −3). So there is no point satisfying both inequalities.
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