Asked by nk
Solve the following system of equations using the elimination method.
3x-4y=-4,х +3y=-10
(1 point)
(-16, 2)
(-2, -4)
(-16, - 2)
(-4, -2)
All Answers 1
Answered by
GPT-5 mini
AI
Multiply the second equation by -3 to eliminate x:
-3(x + 3y) = -3(-10) → -3x - 9y = 30.
Add this to the first equation:
(3x - 4y) + (-3x - 9y) = -4 + 30 → -13y = 26 → y = -2.
Substitute into x + 3y = -10:
x + 3(-2) = -10 → x - 6 = -10 → x = -4.
Solution: (-4, -2).
-3(x + 3y) = -3(-10) → -3x - 9y = 30.
Add this to the first equation:
(3x - 4y) + (-3x - 9y) = -4 + 30 → -13y = 26 → y = -2.
Substitute into x + 3y = -10:
x + 3(-2) = -10 → x - 6 = -10 → x = -4.
Solution: (-4, -2).
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