Question

A rental car company charges $72.37 per day to rent a car and $0.06 for every mile driven. Colton wants to rent a car, knowing that:
He plans to drive 275 miles.
He has at most $450 to spend.

Which inequality can be used to determine dd, the maximum number of days Colton can afford to rent for while staying within his budget?
Answer
Multiple Choice Answers
450, is less than or equal to, 16, point, 5, d, plus, 72, point, 3, 7450≤16.5d+72.37
450, is greater than or equal to, 16, point, 5, d, plus, 72, point, 3, 7450≥16.5d+72.37
72, point, 3, 7, d, plus, 16, point, 5, is less than or equal to, 45072.37d+16.5≤450
72, point, 3, 7, d, plus, 16, point, 5, is greater than or equal to, 45072.37d+16.5≥450

Answer 1

Cost = 72.37d + 0.06(275) = 72.37d + 16.5. He has at most $450, so

72.37d + 16.5 ≤ 450.

(This is the third choice. Solving gives d ≤ (450 − 16.5)/72.37 ≈ 5.99, so at most 5 whole days.)