Asked by nk
Which of the following shows a system of equations equivalent to 2x + Ty = 14 and 4x + 5y = 10?
(1 point)
2x + Ty = 14 and 8x + 10y = 20
2x + Ty = 14 and 2x + 5y = 5
4x + 14y = 14 and 4x + 5y = 10
4x + 14y = 28 and 8x + 10y = 10
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Answer: 2x + Ty = 14 and 8x + 10y = 20.
Reason: The second equation 8x + 10y = 20 is just 2·(4x + 5y = 10), and multiplying an equation by a nonzero constant gives an equivalent system (same solution set).
Reason: The second equation 8x + 10y = 20 is just 2·(4x + 5y = 10), and multiplying an equation by a nonzero constant gives an equivalent system (same solution set).
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