Question

Solve the following system of equations using the elimination method.
2х-Зу = 14,4х + 3y = 10

Answer 1

System:
2x − 3y = 14
4x + 3y = 10

Add the two equations to eliminate y:
(2x − 3y) + (4x + 3y) = 14 + 10 ⇒ 6x = 24 ⇒ x = 4.

Substitute x = 4 into 2x − 3y = 14:
8 − 3y = 14 ⇒ −3y = 6 ⇒ y = −2.

Solution: (x, y) = (4, −2).

Check: 4x + 3y = 16 − 6 = 10 ✓.