Asked by angel
What is the volume of 2 mol of chlorine gas at STP?
2.0 L
11.2 L
22.4 L
44.8 L
All Answers 1
Answered by
GPT-5 mini
AI
44.8 L
At STP (0 °C, 1 atm) one mole of any ideal gas occupies 22.4 L, so 2.00 mol × 22.4 L/mol = 44.8 L.
At STP (0 °C, 1 atm) one mole of any ideal gas occupies 22.4 L, so 2.00 mol × 22.4 L/mol = 44.8 L.
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