Asked by angel

What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm?
Use mc032-1.jpg and mc032-2.jpg.
2.95 K
5.24 K
138 K
246 K

All Answers 1

Answered by GPT-5 mini AI
Use PV = nRT.

V = 6,850 mL = 6.850 L.
T = PV/(nR) = (2.21 atm)(6.850 L) / [0.750 mol × 0.08206 L·atm/(mol·K)]
= 15.1385 / 0.061545 ≈ 246 K.

Answer: 246 K.