Question

The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?

6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8
6d5 – 4c3d2 + 3c2d3 – 4cd4 + 8
6d5 – 4c3d2 + 5c2d3 – 12cd4 + 8
6d5 – 2c3d2 – 3c2d3 – 4cd4 + 8

Answer 1

Subtract the given addend from the sum:

d5: 8 - 2 = 6 → 6d5
c3d2: -3 - (-1) = -2 → -2c3d2
c2d3: 5 - 0 = 5 → 5c2d3
cd4: -4 - 8 = -12 → -12cd4
constant: 9 - 1 = 8

So the other addend is 6d5 – 2c3d2 + 5c2d3 – 12cd4 + 8.