Question

solve 2x^2+5x+3=0
.

Round your answer to the tenths, if necessary.

Answer 1

Use the quadratic formula: x = [-b ± √(b²−4ac)]/(2a) with a=2, b=5, c=3.

Discriminant = 5² − 4·2·3 = 25 − 24 = 1.

x = (−5 ± 1)/(4) → x = (−5+1)/4 = −1.0 and x = (−5−1)/4 = −1.5.

Rounded to tenths: x = −1.5 and x = −1.0.