Question

What is the energy of a photon with a frequency of 3.6 × 1015 Hz? Planck’s constant is 6.63 × 10–34 J•s.

1.8 × 10–49 J
2.4 × 10–19 J
1.8 × 10–18 J
2.4 × 10–18 J

Answer 1

E = hf = (6.63×10⁻³⁴ J·s)(3.6×10¹⁵ Hz) = 2.3868×10⁻¹⁸ J ≈ 2.4×10⁻¹⁸ J.

Answer: 2.4 × 10⁻¹⁸ J (option 4).