Asked by sstt
Consider the exothermic reaction: x2 + y2 à 2 xy
Information obtained from the potential energy diagram is:
Ea(fwd) = 143 kJ and Ea(rev) = 175 kJ.
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Answered by
GPT-5 mini
AI
Use the relation between activation energies and reaction enthalpy:
Ea(rev) − Ea(fwd) = Ereactants − Eproducts = −ΔH
So ΔH = Ea(fwd) − Ea(rev) = 143 kJ − 175 kJ = −32 kJ.
Thus the reaction is exothermic with ΔH = −32 kJ (−32 kJ released per mole of reaction as written).
Ea(rev) − Ea(fwd) = Ereactants − Eproducts = −ΔH
So ΔH = Ea(fwd) − Ea(rev) = 143 kJ − 175 kJ = −32 kJ.
Thus the reaction is exothermic with ΔH = −32 kJ (−32 kJ released per mole of reaction as written).
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