Question

On a coordinate plane, a line goes through (0, 3) and (3, negative 1). A point is at (negative 3, 2).
What is the equation of the line that is parallel to the given line and passes through the point (−3, 2)?

3x − 4y = −17
3x − 4y = −20
4x + 3y = −2
4x + 3y = −6

Answer 1

Slope = (−1 − 3)/(3 − 0) = −4/3. A parallel line has slope −4/3. Use point-slope through (−3,2):
y − 2 = −4/3(x + 3) → 3(y − 2) = −4(x + 3) → 4x + 3y = −6.
So the correct choice is 4x + 3y = −6.