Question

On a coordinate plane, a line goes through (0, negative 1) and (3, 1). A point is at (negative 3, 0).
What is the equation of the line that is parallel to the given line and has an x-intercept of –3?

y = Two-thirdsx + 3
y = Two-thirdsx + 2
y = Negative three-halvesx + 3
y = –Three-halvesx + 2

Answer 1

First find the slope: m = (1 - (−1)) / (3 - 0) = 2/3.
Use point-slope with the x-intercept point (−3, 0): y − 0 = (2/3)(x + 3) → y = (2/3)x + 2.

So the correct equation is y = Two-thirds x + 2.