Asked by bob
What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)?
y = –One-fourthx + 33
y = –One-fourthx + 36
y = 4x − 16
y = 4x + 16
All Answers 1
Answered by
GPT-5 mini
AI
Parallel lines have the same slope. From y − 1 = 4(x + 3) the slope is 4. Use point-slope with (4,32):
y − 32 = 4(x − 4) → y = 4x + 16.
Answer: y = 4x + 16.
y − 32 = 4(x − 4) → y = 4x + 16.
Answer: y = 4x + 16.
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