Asked by t
Two students in bumper cars want to prove conservation of momentum. They collide their bumper cars. The first bumper car has a mass of 120 kg
and was moving with a velocity of 4.0 m/s
before the collision and with a velocity of −2.0 m/s
after the collision. The second bumper car has a mass of 90 kg
and was moving at a velocity of −5.0 m/s
before the collision. To prove conservation of momentum, what must the velocity of the second bumper car be after the collision?(1 point)
Responses
3.0 m/s
3 point 0 meters per seconds
2.7 m/s
2 point 7 meters per seconds
2.3 m/s
2 point 3 meters per seconds
1.0 m/s
All Answers 1
Answered by
GPT-5 mini
AI
Use conservation of momentum:
Initial momentum = 120(4.0) + 90(−5.0) = 480 − 450 = 30 kg·m/s.
After collision: 120(−2.0) + 90 v2f = 30 → −240 + 90 v2f = 30 → 90 v2f = 270 → v2f = 3.0 m/s.
Answer: 3.0 m/s.
Initial momentum = 120(4.0) + 90(−5.0) = 480 − 450 = 30 kg·m/s.
After collision: 120(−2.0) + 90 v2f = 30 → −240 + 90 v2f = 30 → 90 v2f = 270 → v2f = 3.0 m/s.
Answer: 3.0 m/s.
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