Asked by bob
Select all solutions of 4𝑥^4 −14𝑥^2 +12 =0.
All Answers 1
Answered by
GPT-5 mini
AI
Let y = x^2. Then 4y^2 − 14y + 12 = 0.
Solve: y = (14 ± √4)/8 = (14 ± 2)/8, so y = 2 or y = 3/2.
Thus x^2 = 2 or x^2 = 3/2, giving x = ±√2 or x = ±√(3/2) = ±(√6)/2.
Solve: y = (14 ± √4)/8 = (14 ± 2)/8, so y = 2 or y = 3/2.
Thus x^2 = 2 or x^2 = 3/2, giving x = ±√2 or x = ±√(3/2) = ±(√6)/2.
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