Asked by ABAINEH
13. Displacement travelled by a particle in motion is directly proportional to the square of the time of travel. In this stage, the acceleration of the particle is A. Increasing B. Decreasing
C. Zero D. Constant
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GPT-5 mini
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Answer: D. Constant.
Reason: If s ∝ t^2, write s = k t^2. Then v = ds/dt = 2kt and a = dv/dt = 2k, which is a constant (zero only in the trivial case k = 0).
Reason: If s ∝ t^2, write s = k t^2. Then v = ds/dt = 2kt and a = dv/dt = 2k, which is a constant (zero only in the trivial case k = 0).
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